AMCAT DETAILS comes again with another compilation of Quantitative questions with detailed explanation which will be beneficial for students in terms of their preparation for AMCAT.
USE IT BY SUBSTITUTING AND MATCH FROM OPTION GIVEN
Question: The product of two numbers is 9375 and the quotient, when the larger one is divided by the smaller, is 15. The sum of the numbers is:
a) 380
b) 395
c) 400
d) 425
Answer: (c)
Detailed Explanation:
Let the larger number be x
and let the smaller number be y
According to question
x*y=9375 -------1
x/y=15 -------2
Multiplying equation 1 and equation 2 we get,
x^2=140625
=> x=375
Now, just put the value of x in equation 2
then we get y= 25
Since sum of number must be x+y
375+25= 400
and let the smaller number be y
According to question
x*y=9375 -------1
x/y=15 -------2
Multiplying equation 1 and equation 2 we get,
x^2=140625
=> x=375
Now, just put the value of x in equation 2
then we get y= 25
Since sum of number must be x+y
375+25= 400
Therefore the answer is : (c)
Question: A cycled from P to Q at 10 kmph and returned at the rate of 9 kmph. B cycled both ways at 12 kmph. In the whole journey B took 10 minutes less than A. Find the distance between P and Q.
a) 3.75
b) 32.5
c) 37.5
d) 3.25
Answer: (a)
Detailed Solution:
We know that Time = Distance/Speed
Let Time taken by A is Ta and time taken by B is Tb.
Let D be the Distance.
Then,
Ta = (D/10 + D/9) = (19D/90) hrs
Tb = (D/12 + D/12) = (D/6) hrs
Tb = (Ta - 10 minutes)
= (Ta - (1/6)hours)
Ta = (D/10 + D/9) = (19D/90) hrs
Tb = (D/12 + D/12) = (D/6) hrs
Tb = (Ta - 10 minutes)
= (Ta - (1/6)hours)
=> D/6 = (19D/90) - (1/6)
=> 1/6 = (19D-15D)/90
=> 15 = 4D
=> D = 3.75 km
=> 1/6 = (19D-15D)/90
=> 15 = 4D
=> D = 3.75 km
Therefore, the answer is a.
Question: If QUESTION =DOMESTIC what will b code for RESPONSE ????
(a) OMESUCEM
(b) OMESICSM
(c) OMESICEM
(d) OMESISCM
Answer: (c)
Detailed Explanation:
We can solve this question by comparing each characters in the given question.
Since QUESTION=DOMESTIC
USE E=M,S=E,O=I,N=C,S=E.USE IT BY SUBSTITUTING AND MATCH FROM OPTION GIVEN
That is:
R=O
E=M
S=E
P=S
O=I
N=C
S=E
E=M
E=M
S=E
P=S
O=I
N=C
S=E
E=M
Therefore the answer is c.
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